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Arte-miy333 [17]
3 years ago
14

Q(–1, a) is 4 √5 units away from P(3, –2). Find all possible values of a.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

a=6,-10

Step-by-step explanation:

4\sqrt{5}=\sqrt{(3+1)^2+(-2-a)^2} \\squaring\\80=16+(2+a)^2\\80-16=(2+a)^2\\(a+2)^2=64\\taking~square ~root\\\\a+2=\pm 8\\either \\a+2=8,\\a=8-2=6\\or\\a+2=-8\\a=-8-2=-10

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Answer:

Circumference

Step-by-step explanation:

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3 years ago
N is a positive integer
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Part (1)

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This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

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The result 2m is even showing that n(n-1) is even

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Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

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So overall, n(n-1) is even regardless if n is even or if n is odd.

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Part (2)

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Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

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2 years ago
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