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stellarik [79]
3 years ago
11

If theirs 50 questions on a test how many do you have to get wrong to get the lowest grade

Mathematics
1 answer:
Vesna [10]3 years ago
3 0
To get the lowest grade is get all of them inccorect, which is 0% , which is the lowest grade.
Hope this helps! Can i get brainiest?
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Is 13 a perfect cube , perfect square , or neither
denis-greek [22]

Answer:

neither

Step-by-step explanation:

if we cube root or square root thirteen, the result will be in decimal. So thirteen is neither a perfect square nor a perfect cube

Please mark as brainliest

5 0
3 years ago
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A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probability that it bea
777dan777 [17]

Answer:

a) 4/65 b) 13/65 c) 12/65 d) 19/65

Step-by-step explanation:

Probability is the likelihood or chance that an event might occur.

Probability = expected outcome of event/Total outcome of event

If a box contains cards bearing numbers from 6 to 70, the total outcome will be the total number present from 6 to 70 which is 65

a) The amount of one digit number we have are 4 i.e {6,7,8,9}. This will be our expected outcome in this case.

The probability that the number drawn bears a one digit number will be 4/65

b) For numbers divisible by 5, the numbers that are divisible by 5 from the number drawn are {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70}

The total expected outcome in this case = 13

The probability that the number drawn is divisible by 5 = 13/65

c) For odd numbers less than 30, they are {7,9,11,13,15,17,19,21,23,25,27,29}

The total expected outcome in this case = 12

The probability that the number drawn are odd numbers less than 30 = 12/65

d) For composite number between 50 and 70, this are numbers that are within this range and they includes {51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69}

The total expected outcome in this case = 19

The probability that the number drawn are composite numbers between 50 and 70= 19/65

8 0
3 years ago
-6y + 10 = 8<br> I need to solve for y
Radda [10]

Answer:

\frac{1}{3}

Step-by-step explanation:

I did this bfor. You have got to trust me.

8 0
3 years ago
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How can you get to 62 by using 2?
zhannawk [14.2K]
Could you do 31 add 31 which would also be 31 multiplyed by 2
hope this helps

8 0
3 years ago
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What is the answer to the question A 0.10
xenn [34]
Yeah it’s A q0 good luck
3 0
3 years ago
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