If you're trying to say what's 90% of 63, you divide 63 by 10 which is 6.3 then times by 9 which is 56.7
Answer:
20%
Step-by-step explanation:
4/5=.80
1-.80=.20
.20=20%
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
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Answer:
x= -3/4 or -0.75
Step-by-step explanation:
1) subtract 7 from both sides which would make it
-3x= 5x+6
2) Subtract 5x from both sides which would make it
-8x-6
3) Divide both sides by -8
which gives you -3/4
Answer:
w x 3 or w(3) or even w3
Step-by-step explanation:
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