Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
The answer would be
A. 3/4
Answer:
Step-by-step explanation:
Hello,
we assume that a is different from 0 otherwise there is not much we can say on c and then we can write
a(c+b)=d
<=> ac+ab=d
<=> ac = d - ab
<=> 
Hope this helps
We have that
A(-4,-4) B(-2,5) C(2,1) D(2,-4)
step 1
find the distance AC with the formula
d=√[(y2-y1)²+(x2-x1)²]------> dAC=√[(1+4)²+(2+4)²]----> dAC=√61 units
dAC=√61-----> dAC=7.8 units
the answer is
the option
<span>B. 7.8 units</span>
Answer:
equation could represent the total cost (y), in dollars, for x teacher ... first 3 days she takes care of a dog and $25 for each day thereafter..... An amusement park has a group rate.
