The answer to this problem is A
2 surfaces are 6 in by 9 in, meaning that their combined area is 2(54 in^2).
2 surfaces are 6 in by 18 in; combined area is 2(108 in^2).
2 surfaces are 9 in by 18 in; combined area is 2(162 in^2).
Add up these areas: A = 2(54+108+162) in^2 = 648 in^2 (answer)
The solution to the inequality would be: B) (1, 1)
BHF= 106
HGD=106
EGD = 74
EGC= 106
May be wrong but hope this helped!
a. vertical angles are congruent
b. congruence of angles is transitive
c. if two lines are cut by a transversal such that alternate interior angles are congruent, then the lines are parallel
