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Studentka2010 [4]
3 years ago
10

If x + 3 3 = y + 2 2 ,then x 3 =

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

I believe the answer is y/2 but I'm not entirely sure

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In a sample of 1000 cases, the mean of a certain test is 14 and the standard deviation is 2.5. Assume the distribution to be nor
Maslowich

Answer:

The top 20% of the students will score at least 2.1 points above the mean.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The mean of a certain test is 14 and the standard deviation is 2.5.

This means that \mu = 14, \sigma = 2.5

The top 20% of the students will score how many points above the mean

Their score is the 100 - 20 = 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.84.

Their score is:

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 14}{2.5}

X - 14 = 0.84*2.5

X = 16.1

16.1 - 14 = 2.1

The top 20% of the students will score at least 2.1 points above the mean.

7 0
3 years ago
Use the product rule to simplify sq root 147x^2
klio [65]

Answer:7x√3

Step-by-step explanation:

√147x^2

√49 (3) x^2

√7^2 ⋅ 3x^2

√7^2x^2 ⋅ 3

√(7x)^2 ⋅ 3

7x√3

3 0
3 years ago
Solve this!
Reptile [31]
Withdraw- remove
Deposit- put
Discount- take off
5 0
3 years ago
Help me please, i just need an answer
Kruka [31]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
This is adding linear equations:
Kipish [7]
1. -x-1
2. -10x+9
3. -3x+1
4. -4.8x-0.8
5. -1.25x-0.7
6. -6x-20
7. 10x+10
8. -x+16

You’re welcome
4 0
3 years ago
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