All categories

3 years ago

Find the sum and express it in simplest form (6y-2c+2)+(-3y+4c)

1 answer:

Taya2010 [7]3 years ago

3 0

Well, kid all you have to do is add like terms and place the subjected terms in alphabetical order.
1. (6y-2c+2)+(-3y+4c)
2. 6y + - 3y = 3y
3. -2c+4c =2c
4. the positive in the first set of parenthesis has to term other than its number by itself. (so it remains alone and only positive 2)
5. take all the separate term answers and add them into a complete expression- 3y + 2c + 2: and that is all

You might be interested in

Find - 36<br> .<br> Ο +6<br> -6<br> 9Ο<br> Ο 18

Alinara [238K]

Answer:

+or-6

Step-by-step explanation:

This is a trick question. The answer would be the first choice since you're multiplying -6 by +or-6, meaning that it could still end up as a negative or a positive.

3 0

3 years ago

Read 2 more answers

What is the general form of the equation of the line shown?

Arturiano [62]

The answer is A, because the Y-intersect starts at -2

6 0

3 years ago

Read 2 more answers

Help!! Which of the following best represents Z1 • Z2 select all that apply

AURORKA [14]

$z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)$

$z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}$

$\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}$

$\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\$

$Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)$

$=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)$

On simplifying, we get

$Z_1* Z_2 =-3\sqrt{2}$

<h2>Therefore, correct option is 1st option.</h2>

3 0

3 years ago

10 POINTS AND WILL GIVE BRAINLIEST

Vladimir [108]

${3}^{ - 2x} = { (\frac{1}{ {3}^{2} } )}^{x} = ( { \frac{1}{9} )}^{x} an \\ exponential \: function \: of \: the \: form \\ f(x) = a \times {b}^{x} \: with \: a \: = 1 \: and \\ b = \frac{1}{9}$

8 0

3 years ago

Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.

serious [3.7K]

The greatest number of sandwiches that Olivia can make is 12.

3 slices of cheese will be on each sandwich

<u>Solution:</u>

Given that, Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.

We have to find what is the greatest number of sandwiches that Olivia can make? And how many slices of cheese will be on each sandwich?

Let the number of sandwiches be "n"

Then, number of slices of ham per sandwich $=\frac{48}{n}$

And, number of slices of cheese per sandwich $=\frac{36}{n}$

As slices can’t be fractions, "n" should be a factor of 48 and 36. So now let us find H.C.F of 48 and 36 as we want greatest number of sandwiches that Olivia can make.

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36

The common factors are those which appear on both factors of 48 and 36 are 1, 2, 4, 6, and 12.

Out of these common factors, 12 is the greatest

So, H.C.F of 48 and 36 is 12, which means n = 12

Then, number of cheese slices per sandwich $=\frac{36}{12}=3$

Hence, 12 sandwiches can be made with 3 slices of cheese per sandwich.

8 0

4 years ago