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2 years ago

8

Mathematics

2 answers:

3241004551 [841]2 years ago

7 0

I'm sorry I don't know

VMariaS [17]2 years ago

3 0

Answer:

Good luck Dude

Step-by-step explanation:

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At a middle school, 30% of the

Llana [10]

Answer:

I don't understand percentages

3 0

3 years ago

Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. Which equation shows

juin [17]

Answer:

$\frac{AB}{A''B''} = \frac{1}{4}$

Step-by-step explanation:

Given the information:

A'B'C' reflection over x = −1
dilation by a scale factor of 4 from the origin

<=> the two triangles are similar to each other, triangles are similar if they have the same shape, but can be different sizes, so A″B″C″ is 4 time bigger than ABC

=> the relationship between ΔABC and ΔA″B″C″

= $\frac{AB}{A''B''} = \frac{1}{4}$

We choose C.

Hope it will find you well.

7 0

3 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

3 years ago

Please help me solve this problem

Irina18 [472]

DF is half of AC, so DF=25

7 0

3 years ago

Show all work please!!!!!!

sergij07 [2.7K]

The midpoint formula is:
(point1 + point2)/2

1) (-2 + 12)/2 = 5

2) (-1 +5)/2 = 2
    (0+2)/2 = 1
     (2,1)

3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
     sqrt of (7 -1)^2 + (-7 - 1)^2
     sqrt of (6)^2 + (-8)^2
     sqrt of 36 + 64
     sqrt of 100
     10

Hope this helps!

7 0

3 years ago