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sergeinik [125]
4 years ago
5

Solve for X. Assume X is a 2 x 2 matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluat

ed. [9 9 - 9 -9] x + [6 3 7 9] = [-1 8 -4 6] x.
Mathematics
1 answer:
7nadin3 [17]4 years ago
3 0

Answer:

X=\left[\begin{array}{cc}-\frac{97}{145}&-\frac{54}{145}\\\\\frac{20}{29}&\frac{21}{29}\end{array}\right]\\

Step-by-step explanation:

\left[\begin{array}{cc}9&9\\-9&-9\end{array}\right] X+\left[\begin{array}{cc}6&3\\7&9\end{array}\right] =\left[\begin{array}{cc}-1&8\\-4&6\end{array}\right] X

Assume\:\:\:X=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

9a+9c+6=-a+8c\\-9a-9c+7=-4a+6c\\9b+9d+3=-b+8d\\-9b-9d+9=-4b+6d

10a+c=-6\\5a+15c=7

a=-\frac{97}{145} ,\:\:c=\frac{20}{29}

10b+d=-3\\5b+15d=9

b=-\frac{54}{145} ,\:\:d=\frac{21}{29}

Hence,

X=\left[\begin{array}{cc}-\frac{97}{145}&-\frac{54}{145}\\\\\frac{20}{29}&\frac{21}{29}\end{array}\right]\\

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sergij07 [2.7K]

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7 0
4 years ago
Read 2 more answers
What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC
marta [7]

Answer:

C. B(x,y) = \left(3,-\frac{16}{3} \right)

Step-by-step explanation:

Let A(x,y) = (6,-7), B(x,y) = (x,y) and C(x,y) = (-3,-2). From statement we know that AB = \frac{1}{2}\cdot BC, which is equivalent to the following linear algebraic formula:

B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)] (1)

B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)

\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)

B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y) (2)

Then, the coordinates of point B on AC are:

B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)

B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)

B(x,y) = \left(3,-\frac{16}{3} \right)

Which means that correct answer is C.

5 0
3 years ago
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m1 * m2 = -1

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m2 = -2

y = -2x + b
 

2 = -4  +b

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</span>
8 0
4 years ago
No step by steps or links please
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Answer:

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