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3 years ago

9

The teams are trying to defend their goal and scoring in the opponent's goal even if their opponent's score is higher than them.

what values is shown in this situation

1 answer:

Novay_Z [31]3 years ago

3 0

Answer:

However, if the initial receiving team only scores a field goal, the game is not automatically over and the other team is given an opportunity .

sana makatulong

Step-by-step explanation:

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I need help , so help me.

UkoKoshka [18]

Answer: -30

Step-by-step explanation:

7 0

3 years ago

The Department of Streets of a city has a budget of $1,962,800 for resurfacing roads and hiring additional workers this year. Th

Norma-Jean [14]

Answer:

d \large \frac{1,962,800-84,000m}{36,000}=

e \large 84,000m+36,000w=1,962,800

Step-by-step explanation:

Given the following :

Budgeted amount = $1,962,800

Cost of resurfacing a mile of 2- lane road = $84,000

Salary of additional worker = $36,000

Number of miles = m

Number of workers = w

equations that represents the relationship between the miles of 2-lane roads the department could resurface, m, and the number of new workers it could hire, w, if it the entire budget is spent ;

(Cost of a mile of 2-lane road * number of miles) = total budget

(84000m + 36000w) = 1,962,800

To make w, the subject of the formula :

36000w = 1962800 - 84000m

w = (1962800 - 84000m) / 36000

To make m, the subject of the formula :

84000m = 1962800 - 36000w

m = (1962800 - 36000w) / 84000

4 0

4 years ago

Convert 0:48 to a percent and a simplified fraction

just olya [345]

The answer to this question is 2/5

6 0

3 years ago

For what value of a does (1/9)^a+1 =81^a+1 x 27^2-a ?<br><br>-4<br>-2<br>2<br>6

EastWind [94]

Answer:

- 4

Step-by-step explanation:

Using the rule of exponents

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

$(\frac{1}{9}) ^{a+1}$ = $9^{-(a+1)}$ = $3^{-2(a+1)}$

and right side

= $3^{4(a+1)}$ × $3^{3(2-a)}$

Hence

$3^{-2a-2}$ = $3^{4a+4}$ × $3^{6-3a}$

$3^{-2a-2}$ = $3^{a+10}$

Equating exponents on both sides gives

a + 10 = - 2a - 2 ( add 2a to both sides )

3a + 10 = - 2 (subtract 10 from both sides )

3a = - 12 ( divide both sides by 3 )

a = - 4

4 0

4 years ago

Read 2 more answers

What adds to 10 and multiplies to -300

Anton [14]

X+Y=10
XY=-300

Solve for one of the variables

X=10-Y

Plug into the other equation

Y(10-Y)=-300

Now, you have a quadratic...

-y²-10y+300=0

I would multiply everything by -1, so there's no coefficient on y²

y²+10y-300=0

And solve...

-10±√(100-4(-300))
----------------------------
2

Y=-5±5√(13)

Plug back onto original equation...

X+(-5±5√(13))=10
X±5√(13)=15
X=15±5√(13)

Note: There are 2 sets of answers, keep the negatives with the negatives, and the positives with the positives when dealing with the ±.

8 0

4 years ago