Answer:
ok the anwser is 3
Step-by-step explanation:
= 3
Answer:
37
Step-by-step explanation:
Find the scale 296/8=37
The do 37 x 1=37
The dimensions of the rectangular base will be 110ft by 330ft the length of the base measures less than 3 times the width
The formula for calculating the perimeter of the rectangular base is expressed as:
P = 2(L +W) where;
L is the length
W is the width
If the length of the base measures less than 3 times the width, then L < 3W
Given that Perimeter = 880feet
Substitute the given value into the formula to get the length
880 = 2(3W+W)
880 = 2(4W)
880 = 8W
W = 880/8
W = 110ft
Since L = 3W
L = 3(110)
L = 330ft
Hence the dimensions of the base will be 110ft by 330ft
Learn more here: brainly.com/question/17474046
Let R be the event that a red card is drawn. There are two red suits of 13
cards each, so there are 26 ways of getting are red card. There are 52 cards
altogether, so the probability of getting a red card is
P(R) = 26
52
=
1
2
.
http://www.math.ttu.edu/~drager/Classes/02Spring/m1430/anse3.pdf
1. Drawn a straight line AB =7 cm with the help of ruler.
2. With the help of compass drawn an arc from A and at the point where it cuts AB from that point made another arc drawn an arc cutting the previous arc.
3. From A drawn a straight line joining the arc and extend it to M.
4. With the help of ruler measured 5 cm and mark it as AC.
5. Joined BC and we get the required triangle.
6. From C drawn an arc and make it cut on AC and BC and from the point it cuts AC and BC drawn arc cutting each other and extend a line from point C extend a line to the point point of intersection of two arc.
7. Similarly we do for A and the point where the two line intersect denoted as O.
8. Made a perpendicular from O on AB this perpendicular will be radius and taking O as centre we draw a circle this is our incircle.
9. And AN is our locus of points equidistant from two lines AB and AC.
We need to construct a circle inscribed in triangle that is incircle it can be done by making angle bisector of two sides the point where it intersect will be incentre. The centre of required circle.
The angle bisector is the locus where points are equidistant from two sides.
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