That day they will have 132 conversations. There are 12 members and each one will be calling the remaining 11 members of the club which means each one will make 11 calls and that will be done by 12 members so 11x12= 132 conversations in total
12 months= 1 year
Every month they make 132 calls so 132x12 will be 1,584 calls per year.
If the club decides to add four new members to the club the conversations each month will rise up to 240.
If the other club likes the idea they can use the following equation
(x-1)(x)
X represents the number of members of the group the subtraction of 1 is when a member makes a call not including them selves so there are 12 members but the one making the call isn't included so there are 11 calls being made then being multiplied by the total number of members.
(x-1)(x)
(12-1)(12)
11(12)
132
Answer
Choice D
Company 2 is greater in avg rate of change by $750
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Explanation:
Average rate of change is the same as slope through two points. The two points are the endpoints of the interval.
The x values we'll use is x = 0 and x = 12 since it constitutes the first 12 years (12-0 = 12)
For company 1, if x = 0 and x = 12, then y = 12000 and y = 30000 respectively. The two points (0,12000) and (12,30000) are on the graph for company 1
The slope of the line through these two points is
m = (y2-y1)/(x2-x1)
m = (30000-12000)/(12-0)
m = 18000/12
m = 1500
Over the first twelve years, the average rate of change for company 1 is 1500
For company 2, the points (0,15000) and (12,42000) are on the graph
The slope of the line through these two points is
m = (y2-y1)/(x2-x1)
m = (42000-15000)/(12-0)
m = (27000)/(12)
m = 2250
Over the first twelve years, the average rate of change for company 2 is 2250
Now find the difference in the slopes
2250-1500 = 750
Company 2's rate of change is larger by $750
So that's why the answer is choice D. Over this timespan, company 2 is growing faster on average compared to company 1
Answer:
1000 cm2
Step-by-step explanation:
Pretty sure
Answer:
15/8 - 6/8= 9/8
Step-by-step explanation:
