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dalvyx [7]
3 years ago
5

Rewrite the following equation in standard form. y + 7 = 2(x - 6)

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

(-5)

Step-by-step explanation:

(-5)+7=2(×-6) fahhshzhsuhshzhhsbwysvavaghahahahwhwgwvavvwhhwshahwh

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4 Move the digits in 625,134 to create a new number.Move the 2 so it is worth 1_10as much.Move the 3 so it is worth 10 times as
Jet001 [13]

Answer:

452,316

Step-by-step explanation:

Why do you need a step by step, and i dont see how you would get one.

5 0
3 years ago
Plz help me!! I need explanation to help me understand a bit.
lozanna [386]
So the figure is called a ray. Which is when there’s a point and than an arrow extends off that point forever. But the way to write a ray is by putting an arrow above it.
3 0
3 years ago
Multiplying (-9)(-6)(2)=
yawa3891 [41]

Answer:

108

Step-by-step explanation:

3 0
3 years ago
A radio station claims that the amount of advertising per hour of broadcast time has an average of 13 minutes and a standard dev
zimovet [89]

Answer:

Z = 3.33

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 13, \sigma = 1.2

You listen to the radio station for 1​ hour, at a randomly selected​ time, and carefully observe that the amount of advertising time is equal to 17 minutes. Calculate the​ z-score for this amount of advertising time.

We have to find Z when X = 17. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 13}{1.2}

Z = 3.33

5 0
3 years ago
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
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