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3 years ago

Solve the equation: 5(y+2)=-35 оа y=-7 y=-17 O oc Od y=-5 y=-9

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

Answer:

y = -9

Step-by-step explanation:

divide by 5 first

y + 2 = -7

-2

y = -9

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Find P 20 of the following arithmetic sequence: 206, 212, 218, 224....

Yanka [14]

Answer:

$p_{20} = 1.25528$

P₀ = 206 and difference d = 6

Step-by-step explanation:

Step(i):-

Given that the arithmetic sequence

206,212,218,224,.....

P₀ = 206 and difference d = 212-206 = 6

The $n^{th}$ term of the sequence

$t_{n} = ar^{n-1}$

Step(ii):-

The $n^{th}$ term of the sequence

$P_{n} = ar^{n-1}$

Put n=20

$P_{20} = 206 ( 6) ^{20-1}$

$p_{20} = 1.25528$

7 0

3 years ago

19= 7a + 7 -2 what is the and to this need help ASAP

____ [38]

Answer:

a = 2

Step-by-step explanation:

19= 7a +5

19-5=7a

14÷7=a

a=2

8 0

3 years ago

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Which expression is equivalent to the given expression 10q + 5

Mice21 [21]

10q + 5 = 5q + 5q + 5

so
answer is

A. 5q+5q+5

3 0

3 years ago

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Fill in the blanks below using the word bank.

Charra [1.4K]

M is the slope.

B is the y-intercept

The constant of proportionality is the ratio between two directly proportional quantities.

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3 years ago

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PLZ HELP, AND PLZ EXPLAIN

shutvik [7]

Answer:

Step-by-step explanation:

To make it easy let's start by organizing our information :

AC=12 AND BD=8
ABCD is a rhombus
K and L are the midpoints of sides AD and CD
we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

The pythagorian theorem !

AC and BD are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

(AC/2)² + (BD/2)² = BC²
6²+4²=52
BC²= 52⇒ $\sqrt{52}$ =BC

Now we khow that : AB=BC=CD=AD= $\sqrt{52}$

This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle

KL is parallel to AC
k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE

KL/12= $\sqrt{52}$ /2* $\sqrt{52}$
KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

notice that you khow the length of KL
BD crosses kl from its midpoint and DL = $\sqrt{52}$ /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

DL²=(KL/2)²+D²
52/4= 9+ D²
D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0

3 years ago