When you reflect a function in the <em>x</em>-axis, the first coordinate of a point stays the same, and the second coordinate changes sign (what was positive is now negative and vice versa). See the attached picture.
Question 11: f(x) = -5x + 2. The function changes to its opposite, so g(x) = -(-5x + 2) = 5x - 2.
When you reflect a function in the <em>y</em>-axis, the first coordinate of a point changes to its opposite, but the second coordinate stays the same. Replace <em>x</em> with -<em>x</em> .
Question 14: f(x) = |2x - 1| + 3. Replacing <em>x</em> with -<em>x</em> produces g(x) = |2(-x) - 1| + 3 which simplifies to g(x) = |-2x -1| + 3.
Question 15 works the same way as #14.
Answer:
https://jbarrueta.weebly.com/uploads/5/3/2/9/53297595/lesson2.2.2.pdf
Step-by-step explanation:
here's a link
Answer:
sorry di ko alam
Step-by-step explanation:
Answer:
485
Step-by-step explanation:
Q(-9) = 6(-9)² - 1 = 6×81 - 1 = 486 - 1 = 485
<span>Simplifying
3x + -1y = 12
Solving
3x + -1y = 12
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add 'y' to each side of the equation.
3x + -1y + y = 12 + y
Combine like terms: -1y + y = 0
3x + 0 = 12 + y
3x = 12 + y
Divide each side by '3'.
x = 4 + 0.3333333333y
Simplifying
x = 4 + 0.3333333333y</span>