1) 4
2) 3520
3) 3.8
4) 84
5) 15840
6) 9
7) 2
8) 24
9) 1.25
Answer:
125
Step-by-step explanation:
TY NOT BRAINLIEST PLEASE
Answer:
Option 4
Step-by-step explanation:
Group B, because seven children have a forearm length longer than 10 inches.
Additional verification :
Finding average forearm length of Group A :
- 9(3) + 10(5) + 11(2) / 10
- 27 + 50 + 22 / 10
- 99/10
- 9.9
Finding average forearm length of Group B :
- 10(3) + 11(4) + 12(3) / 10
- 30 + 44 + 36 / 10
- 100/10
- 10
Group B clearly has the longer forearm length.
Given:
Week 6 = 14 miles
Week 5 = 1.5 miles less than week 6.
1.5 miles is the common difference.
Week 6 = 14 miles
Week 5 = 12.5 miles
Week 4 = 11 miles
Week 3 = 9.5 miles
Week 2 = 8 miles
Week 1 = 6.5 miles
f(t) = first term + common difference(t-1)
f(t) = 6.5 miles + 1.5 miles (t-1)
f(1) = 6.5 + 1.5(1-1)
f(1) = 6.5 miles
f(2) = 6.5 + 1.5(2-1)
f(2) = 6.5 + 1.5
f(2) = 8 miles
Answer:
3x+5y=20
Step-by-step explanation:
