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wlad13 [49]
3 years ago
10

Please help! On Saturday Lucas drove

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

x+5

Step-by-step explanation:

(4x-5) -(3x - 10) = x + 5

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5 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
Indicate whether the function represents an exponential growth or decay.
svetoff [14.1K]

Answer:

1) decay

2) growth

3) growth

Step-by-step explanation:

A generic exponential function can be written as:

f(x) = A*(r)^x

Where:

A is the initial amount of something.

r is the rate of growth.

x is the variable, usually, represents time.

if r > 1, we have an exponential growth.

if r < 1, we have an exponential decay.

1) f(x) = (3/4)^x

in this case we have:

A = 1

r = (3/4) = 0.75

Clearly, r < 1.

Then this is an exponential decay.

2) f(x) = (1/6)*4^x

In this case we have:

A = (1/6)

r = 4

Here we have r > 1.

Then this is an exponential growth.

3) f(x) = (1/4)*(5/2)^x

in this case we have:

A = 1/4

r = 5/2 = 2.5

here we have r > 1, then this is an exponential growth.

8 0
3 years ago
911, What's your Emergency?...Hello, is anyone there?
vampirchik [111]

Answer:

ote! the answer is 1.d 2.d

Step-by-step explanation:

there you go baby girl

8 0
2 years ago
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