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3 years ago

10

Please help! On Saturday Lucas drove

1 answer:

Debora [2.8K]3 years ago

4 0

Answer:

x+5

Step-by-step explanation:

(4x-5) -(3x - 10) = x + 5

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Find the mean and median of these data: 2, 5, 9, 11, 17, 19.

Harrizon [31]

<span>data: 2, 5, 9, 11, 17, 19
</span>
median is the middle number
median = (9+11)/2 = 10

mean = average
mean = (2 + 5 + 9 + 11+ 17 + 19)/6
mean = 63/6
mean = 10.5

6 0

3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

4 years ago

K/75 + 57.1 = 40.8<br> k = ?

Ronch [10]

K/75 + 57.1 = 40.8

k/75 = 40.8 - 57.1

k/75 = -16.3

k = -16.3 • 75

k = -1222.5 or -1222 1/2

Hope it helps!

5 0

3 years ago

In the united states, the five great lakes cover an area of 94,710 square miles. The smallest of the great lakes, lake ontario,

tankabanditka [31]

Solution: We are given:

The area covered by five great lakes in United States $=94,710$ square miles.

The area covered by the smallest of the great lakes, Lake Ontario $=7,540$ square miles.

The fraction of the area of Ontario lake to the total area of all the great lakes is:

$\frac{7,540}{94,710}$

$\frac{754}{9471}$

Therefore, the simplest form of fraction is $\frac{754}{9471}$

$\frac{754}{9471}=0.08$

8 0

3 years ago

Exactly how many plants contain points J, K and N

Evgesh-ka [11]

The contain points j,k and N is = X plants

7 0

3 years ago