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3 years ago

14

Lavonne sold 4 times as many raffle tickets as Kenneth. Lavonne sold 56 raffle tickets. Write and solve an equation to find how

many tickets Kenneth sold

2 answers:

ICE Princess25 [194]3 years ago

8 0

OK, so just do 56 divided by 4 and you can get kenneth's tickets.

Valentin [98]3 years ago

6 0

Lavonne sold 56=4x
so x=56/4=14 Kenneth sold 14 tickets<span />

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Two companies working together can clear a parcel of land in 27 hours. Working alone, it would take Company a 2 hours longer to

algol13

Answer:

53 hours

Step-by-step explanation:

If A is the time it takes Company A, and B is the time it takes Company B, then:

1/27 = 1/A + 1/B

A = B + 2

Substitute and solve:

1/27 = 1/(B + 2) + 1/B

1/27 = (B + B + 2) / (B (B + 2))

1/27 = (2B + 2) / (B² + 2B)

27 (2B + 2) = B² + 2B

54B + 54 = B² + 2B

0 = B² − 52B − 54

B = [ -(-52) ± √((-52)² − 4(1)(-54)) ] / 2(1)

B = (52 ± √2920) / 2

B ≈ 53.0

It would take Company B approximately 53 hours.

5 0

3 years ago

What is the value of x?<br><br> A. 112<br> B. 68<br> C. 62<br> D. 56

ollegr [7]

Answer:

B 68

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

the circumference of the circle shown below is 54 centimeters. which expression gives the length in centimeters of XY?

g100num [7]

Answer:

The correct option is C

Step-by-step explanation:

Given the circumference of circle which is 54 cm and also the measure of arc XY is 120°

we have to find the expression for arc length of XY

The arc length can be calculated by the formula

$\frac{\theta}{360}\times 2\pi r$

$\frac{\theta}{360}\times circumference$

$\frac{120}{360}\times 54$

Hence, option C is correct

4 0

3 years ago

Read 2 more answers

Is this the correct answer to this question?

timama [110]

Sorry, I havent learned that.

8 0

4 years ago

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What is the sum of the first five terms of s geometric series with a1=6 and r=1/3

omeli [17]

$S_{5}$ = $\frac{242}{27}$ = 8 $\frac{26}{27}$

The sum of n terms in a geometric series is

$S_{n}$ = $\frac{a(1-r^n)}{1-r}$ , hence

$S_{5}$ = $\frac{6(1-(1/3)^5)}{1-1/3}$

= $\frac{6(1-1/243)}{2/3}$

= 9 ( $\frac{242}{243}$ ) = $\frac{242}{27}$

7 0

4 years ago