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aev [14]
3 years ago
12

How can i keep my passwords safe?

Mathematics
2 answers:
Yakvenalex [24]3 years ago
7 0

Answer:

Keep your logins locked down with our favorite apps for PC, Mac, Android, iPhone.

Step-by-step explanation:

kifflom [539]3 years ago
3 0

use a capital letter, make it at least 7 letters long, use a special charater(s) (ect. _) and make sure you can remember it

Step-by-step explanation:

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3 years ago
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Another One I need help withhhh sorrry
Effectus [21]

Answer:

y = 2x+3

Step-by-step explanation:

Sorry I'm probably too late since Quizziz doesn't wait unless you have the freeze timer thing.

y = mx+b

b is the y intercept. The y intercept (when x=0) is given in the table.

Now plug a coordinate in to solve for m.

My coordinates: (1,5)

5 = m + 3

Solve.

2 = m

m = 2

Note: never plug in the y intercept when looking for m.

You can also find the slope by (subtracting the y value of one coordinate from another y value of another coordinate)/(subtracting x value from the first y coordinate above from the x value from the second coordinate).

In this case, it'd be

m = (7-5)/(2-1)

m = 2/1

m = 2

6 0
3 years ago
200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

6 0
2 years ago
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