Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla =
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
The side opposite and the hypotenuse are used so you would use sin(29)=14.2/y
Which becomes y=14.2/sin(29) hence =29.28984782 cm. round it as per necessary
Answer:
y = 5-x
Step-by-step explanation:
Given the data:
x -2 1 3 6
y 7 4 2 -1
Linear equation :
y = 5 - x
Answer:
8.1 * 10^-2
Step-by-step explanation:
Scientific notation is a number with it's largest digit in the one's place and its succeeding digits following it as decimals, then multiplied by a power of ten.
Appling this knowledge to the given number, we can conclude:
0.0810
= 0.081
= 8.1 * (1/10) * (1/10)
= 8.1 * 10^-1 * 10^-1
=9.1 * 10^-2
Answer:
B) 10 m
Step-by-step explanation:
Area is 20 and Height is 4
Ok so
AREA of a triangle is =1/2Base Times Height
work back
Area=20
Height=4
b=Base
20=1/2b*4
Simplify both sides of the equation.
20=2b
Flip equation
2b=20
Divide both sides by 2
b=10
Base=10 m