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3 years ago

6

Can someone explain how to get to answer B?

1 answer:

sesenic [268]3 years ago

7 0

Yo have to find the distance between point L and point M. First, you have to do the x values. 1 - -3 = 4. Then, you subtract the y values. -2 - 4 = -6. Next, you add the found numbers to the x and y of the midpoint (m). Leaving 1 +4=5 and -2 + -6 = -8.

(5,-8)

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Write this expression as a single term: 2log2x + log2(x + 5).

ra1l [238]

$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ \log_a(xy)\implies \log_a(x)+\log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2\log_2(x)+\log_2(x+5)\implies \log_2(x^2)+\log_2(x+5) \\\\\\ \log_2[x^2(x+5)]\implies \log_2(x^3+5x^2)$

6 0

4 years ago

If A = 1 2 1 1 and B= 0 -1 1 2 then show that (AB)^-1 = B^-1 A^-1<br><br><br> help meeeee plessss

Trava [24]

$A = \begin{bmatrix}1&2\\1&1\end{bmatrix} \implies A^{-1} = \dfrac1{\det(A)}\begin{bmatrix}1&-1\\-2&1\end{bmatrix} = \begin{bmatrix}-1&1\\2&-1\end{bmatrix}$

where det(<em>A</em>) = 1×1 - 2×1 = -1.

$B = \begin{bmatrix}0&-1\\1&2\end{bmatrix} \implies B^{-1} = \dfrac1{\det(B)}\begin{bmatrix}2&1\\-1&0\end{bmatrix} = \begin{bmatrix}2&1\\-1&0\end{bmatrix}$

where det(<em>B</em>) = 0×2 - (-1)×1 = 1. Then

$B^{-1}A^{-1} = \begin{bmatrix}2&1\\-1&0\end{bmatrix} \begin{bmatrix}-1&1\\2&-1\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}$

On the other side, we have

$AB = \begin{bmatrix}1&2\\1&1\end{bmatrix} \begin{bmatrix}0&-1\\1&2\end{bmatrix} = \begin{bmatrix}2&3\\1&1\end{bmatrix}$

and det(<em>AB</em>) = det(<em>A</em>) det(<em>B</em>) = (-1)×1 = -1. So

$(AB)^{-1} = \dfrac1{\det(AB)}\begin{bmatrix}1&-3\\-1&2\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}$

and both matrices are clearly the same.

More generally, we have by definition of inverse,

$(AB)(AB)^{-1} = I$

where $I$ is the identity matrix. Multiply on the left by <em>A </em>⁻¹ to get

$A^{-1}(AB)(AB)^{-1} = A^{-1}I = A^{-1}$

Multiplication of matrices is associative, so we can regroup terms as

$(A^{-1}A)B(AB)^{-1} = A^{-1} \\\\ B(AB)^{-1} = A^{-1}$

Now multiply again on the left by <em>B</em> ⁻¹ and do the same thing:

$B^{-1}\left(B(AB)^{-1}\right) = (B^{-1}B)(AB)^{-1} = B^{-1}A^{-1} \\\\ (AB)^{-1} = B^{-1}A^{-1}$

7 0

3 years ago

Find the circumference of a circle with a Radius = 4 ft. Use 3.14 for it, and round to 2 decimal places.

Mazyrski [523]

Answer:

Circumference would be 25.12ft

Step-by-step explanation:

So circumference formula is pi(diameter)

We know the radius so to find the diameter we multiply the radius by 2.

so 4(2)=8

and since pi is 3.14 then multiply 8(3.14)

youll get 25.12

3 0

4 years ago

Read 2 more answers

Elsa's magic wand can cast 53 spells. Her wand can cast 17fewer spells than her sister Anna's wand, which is a little bigger and

Mademuasel [1]

Answer:

<em> Anna's wand can cast 70 spells</em>

<em></em>

Step-by-step explanation:

Elsa's wand can cast 53 spells

her wand casts 17 fewer cells than her sister Anna's

Amount of spells cast by Anna's wand = ?

We write the question down in the form of an equation

$x - 17 = 53$

where $x$ is the amount of spells Anna's wand can cast.

we then proceed to solve by collecting like terms to different sides of the equation. We'll have

$x = 53 + 17$

which leaves us with

$x = 70$

This means that<em> Anna's wand can cast 70 spells.</em>

4 0

4 years ago

please help!! 20 points . if you guess or just comment random things to take points i will have you reported and make sure your

mrs_skeptik [129]

Answer:

The first figure is (9, 6, 6)

The second one looks like

10 - 6 = 4

9 x 6 = 54

70 - 54 = 16

The other figure most = 16

4 x 4 = 16

<h2>I think the answer is 4. Forgive me if i'm wrong.</h2>

3 0

3 years ago