Area of square = (length)²
OR

Answer:
Step-by-step explanation:
The graph is that of the basic absolute value function y = |x|, except that the vertex (0, 0) has been translated 4 units to the right and 7 units down.
Answer:
0.00000014972309
Step-by-step explanation:
6/3999=0.00150037509
0.00150037509/10021= 0.00000014972309
hope this helps
![\bf \cfrac{(x-2)(x+3)}{2x+2}\implies \cfrac{x^2+x-6}{2x+2}~~ \begin{array}{llll} \leftarrow \textit{2nd degree polynomial}\\ \leftarrow \textit{1st degree polynomial} \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{vertical asymptote}}{2x+2=0}\implies 2x=-2\implies x=-\cfrac{2}{2}\implies x=-1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%28x-2%29%28x%2B3%29%7D%7B2x%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%5E2%2Bx-6%7D%7B2x%2B2%7D~~%20%5Cbegin%7Barray%7D%7Bllll%7D%20%5Cleftarrow%20%5Ctextit%7B2nd%20degree%20polynomial%7D%5C%5C%20%5Cleftarrow%20%5Ctextit%7B1st%20degree%20polynomial%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bvertical%20asymptote%7D%7D%7B2x%2B2%3D0%7D%5Cimplies%202x%3D-2%5Cimplies%20x%3D-%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%20x%3D-1)
when the degree of the numerator is greater than the denominator's, then it has no horizontal asymptotes.
quick note:
when the degree of the numerator is 1 higher than the degree of the denominator, then it has an slant-asymptote, so this one has a slant-asymptote.
Answer:
x = 14
y = 30
Step-by-step explanation:
x + 10 = 3x - 18
x = 3x - 18 - 10
x = 3x -28
x - 3x = -28
-2x = -28
x = 14
(3x - 18) + (6y - x - 10) = 180
3x - x -18 - 10 + 6y = 180
2x - 28 + 6y = 180
2x + 6y = 180 + 28
2(14) + 6y = 208
6y = 208 - 28
6y = 180
y = 30
I hope this helps!