Answer:
![\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Ctext%7Btherefore%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D)
Answer:
first picture d
second d
third a
forth a
5th c
im not that great at math tho
Step-by-step explanation:
Answer:x=6
Step-by-step explanation:Step-1 : Multiply the coefficient of the first term by the constant 1 • 18 = 18
Step-2 : Find two factors of 18 whose sum equals the coefficient of the middle term, which is -9 .
-18 + -1 = -19
-9 + -2 = -11
-6 + -3 = -9 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -3
x2 - 6x - 3x - 18
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-6)
Add up the last 2 terms, pulling out common factors :
3 • (x-6)
Step-5 : Add up the four terms of step 4 :
(x-3) • (x-6)
Which is the desired factorization
This state action is referred to as monadic. This is a function or a relation with an arity of one. A monad can relate an algebraic theory into a <span>composition of a function though its power is not always apparent.</span>
