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Tanya [424]
3 years ago
10

How to solve 45y to the second power plus 15y minus 10 ?

Mathematics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

Either y =\frac{-2}{3} or, y =\frac{1}{3}

Step-by-step explanation:

We have to solve the following quadratic equation  

45y² + 15y - 10 =0

Now, dividing both sides with 5 we get, 9y² + 3y -2 =0

Hence, to solve the above equation we have to factorize the left-hand part of the equation.

So, 9y² + 3y - 2 =0

⇒ 9y² +6y -3y -2 =0

⇒ (3y +2) (3y -1 ) =0

⇒ Either (3y +2) =0 or (3y -1) =0

⇒ Either y =\frac{-2}{3} or, y =\frac{1}{3} (Answer)

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Ksenya-84 [330]
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3 years ago
X-9/3=56/x+4 solve for x
Flauer [41]

Answer:

x = sqrt(273)/2 - 1/2 or x = -1/2 - sqrt(273)/2

Step-by-step explanation:

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Cross multiply:

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Expand out terms of the left hand side:

x^2 + x - 12 = 56

Add 12 to both sides:

x^2 + x = 68

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Write the left hand side as a square:

(x + 1/2)^2 = 273/4

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Subtract 1/2 from both sides:

x = sqrt(273)/2 - 1/2 or x + 1/2 = -sqrt(273)/2

Subtract 1/2 from both sides:

Answer:  x = sqrt(273)/2 - 1/2 or x = -1/2 - sqrt(273)/2

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