Answer:
Answer D: 8.7 cm
Step-by-step explanation:
First compare the actual diameters of both cables to find out which one is larger. If we write both diameters in fraction form (as they are given), we need to have them expressed with the same denominator for a straight forward comparison:
Bundle A: 
Bundle B: 
So we multiply this last fraction by 2 in numerator and denominator to obtain the same denominator as for Bundle A without actually changing its numerical value: 
So now we compare Bundle A with bundle B, and see that bundle B has the larger diameter: 22/8 inches
The hole has to be 25% larger than this larger diameter, so we estimate 25% of 22/8 in is:
inches
Therefore, the hole must be of diameter 22/8 in plus 0.6875 in = 3.4375 in
Now we convert this value into centimeters by multiplying it by 2.54 (since one inch is 2.54 cm):
3.4375 * 2.54 = 8.73125 cm
which rounded to the nearest tenth as requested in the problem is: 8.7 cm
Answer:
I’m sorry. I don’t know the answer but if u take a picture it on photomath u will get the answer
Step-by-step explanation:
Answer:
A= 1,0 B=0, -3 C=-6, 5 D= -3, -5
Using algebra...
n and n+2 are the integers
n*(n+2)=288
n^2+2n=288
n^2+2n-288=0
288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor
(n+18)(n-16)=0
n+18=0
n=-18
n+2=-16
this is one solution
n-16=0
n=16
n+2=18
this is another solution
as you can see, it's just a matter of factoring
288
using arithmetic...
√288=16.97≈17
16 and 18 are the integers (as well as -16 and -18)
The answer would be D: $162 because $120 x 35% or (0.35) = $42 so $120 + $42 gives you $162