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k0ka [10]
3 years ago
13

Hey come join! tzq axks npa go ogle me et

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

sure :)

Step-by-step explanation:

strojnjashka [21]3 years ago
4 0

No. Sir

Study First. Do your Activities or Modules

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What is the solution for the system of equations? Use the substitution method to solve.
Paraphin [41]
Y = 5 - 3x....so sub in 5 - 3x for y in the other equation

5x - 4y = -3
5x - 4(5 - 3x) = -3.....distribute the -4 thru the parenthesis
5x - 20 + 12x = -3...add 20 to both sides
5x + 12x = -3 + 20...combine like terms
17x = 17...divide both sides by 17
x = 17/17
x = 1

now sub 1 in for x into either of the original equations to find y
y = 5 - 3x
y = 5 - 3(1)
y = 5 - 3
y = 2

check...
5x - 4y = -3
5(1) - 4(2) = -3
5 - 8 = -3
-3 = -3 (correct)

so ur solution is (1,2)
3 0
3 years ago
When you answer on a lot of posts anf now your phone is having a notification rave- ​
mamaluj [8]

Haha! I know how that feels

3 0
3 years ago
Sin(x)^4+ cos(x)^4=1/2
posledela
I'll assume that what was meant was \sin ^4 x + \cos ^4 x = \dfrac{1}{2}.

The exponent in the funny place is just an abbreviation:   \sin ^4 x = (\sin x)^4.

I hope that's what you meant. Let me know if I'm wrong.

Let's start from the old saw

\cos^2 x + \sin ^2x = 1

Squaring both sides,

(\cos^2 x + \sin ^2x)^2 = 1^2

\cos^4 x + 2 \cos ^2 x \sin ^2x +\sin ^4x = 1

\cos^4 x + \sin ^4x = 1 - 2 \cos ^2 x \sin ^2x

So now the original question 

\sin ^4 x + \cos ^4 x = \dfrac{1}{2}

becomes
1 - 2 \cos ^2 x \sin ^2x = \dfrac{1}{2}

4 \cos ^2 x \sin ^2x = 1

Now we use the sine double angle formula

\sin 2x = 2 \sin x \cos x

We square it to see

\sin^2 2x = 4\sin^2 x \cos^2 x = 1

Taking the square root,

\sin 2x = \pm 1

Not sure how you want it; we'll do it in degrees. 

When we know the sine of an angle, there's usually two angles on the unit circle that have that sine.  They're supplementary angles which add to 180^\circ.  But when the sine is 1 or -1 like it is here, we're looking at 90^\circ and -90^\circ, which are essentially their own supplements, slightly less messy. 

That means we have two equations:

\sin 2x = 1 = \sin 90^\circ

2x = 90^\circ + 360^\circ k \quad integer k

x = 45^\circ + 180^\circ k

or 


\sin 2x = -1 = \sin -90^\circ

2x = -90^\circ+ 360^\circ k

x = - 45^\circ + 180^\circ k

We can combine those for a final answer,

x = \pm 45^\circ + 180^\circ k \quad integer k

Check.  Let's just check one, how about

x=-45^\circ + 180^\circ = 135^\circ

\sin(135)= 1/\sqrt{2}

\sin ^4(135)=(1/\sqrt{2})^4 = 1/4

\cos ^4(135)=(-1/\sqrt{2})^4 = 1/4

\sin ^4(135^\circ) +\cos ^4(135^\circ) = 1/2 \quad\checkmark


6 0
3 years ago
What’s the hypotenuse
jeka94

Answer:

17

Step-by-step explanation:

see attached for reference

for the given right triangle, applying the Pythagorean formula gives us:

c² = 15² + 8²

c² = 225+64

c² = 289

c = √289

c = 17 mm

5 0
3 years ago
Read 2 more answers
Sofia and Diego drive to work. Sofia drives 72 miles in 1.5 hours. Diego drives 126 km in 2 hour 30 min. Work out the difference
sdas [7]

Answer:

26.4 km/hr

Step-by-step explanation:

Sofia and Diego drive to work.

For Sofia

We convert miles to km

Sofia drives 72 miles in 1.5 hours.

1 mile = 1.6 km

72 miles = x

x = 72 × 1.6 km

x = 115.2 km

We find the speed in km/hr

Speed = Distance /Time

= 115.2km/1.5 hours

= 76.8 km/hr

For Diego

Diego drives 126 km in 2 hour 30 min.

Speed = Distance/Time

Time = 2 hour 30 min = 2.5 hours

Speed = 126km/2.5 hours

= 50.4 km/hr

The difference between their average speeds in km/h is calculated as:

76.8 km/hr - 50.4 km/hr

= 26.4 km/hr

5 0
3 years ago
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