3 years ago

NEED help with homework

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

42.7/7= 6.1
36.48/6=6.08
7.29/9=0.81

You might be interested in

Rewrite x^5+5r^3-9r+1 in the form q(x)+r(x)/b(x). What is q(x)?

Alex787 [66]

Answer:

a is the correct answer

Step-by-step explanation:

7 0

3 years ago

A group of six tourists arrive at an airport gate 15 minutes before flight time, but only two seats are available.

melomori [17]

8 different groups are aloud in the plane

8 0

3 years ago

Read 2 more answers

What is the value of 2xy if x = 3 and y = 2

romanna [79]

Substitute the values.
2(3)(2)=?
2*3=6
6*2=12
Final answer: 12

8 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

4 0

3 years ago

PLs help I will def make you brainlist pls help both 8,9

Liono4ka [1.6K]

Answer:

The answers are A and C

Step-by-step explanation:

Have a good day

5 0

3 years ago