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2 years ago

How do I find the answer to this.

Mathematics

1 answer:

Maksim231197 [3]2 years ago

7 0

I am sure u have to separate the number with their variables so (4x) (2y -y ) (40+10)
Remember that you have to remove the brackets and u should have 4x - 1y + 50 then 4\4 and 50/4 = four cancles out 4 so we have 1y + 12.5 divide each by one one cancles out 1 = 12.5 round it up to 13 but I suggest u check this with anyone else you can but if my math is correct it should be the closest answer

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Find the area of the shaded regions. GIve your answer as a completely simplified exact value in terms of pi. (No approximations)

Anon25 [30]

Answer:

A = 27π cm²

Step-by-step explanation:

Area of the shaded region = area of full circle of O - Area of the unshaded sector

= (πr²) - (θ/360*πr²)

Where,

r = 6 cm

θ = 360

Area of shaded region = (π*6²) - (90/360*π*6²)

= (36π) - (¼*π*36)

= 36π - 9π

Area of shaded region = 27π cm²

4 0

2 years ago

Find the midpoint of AB for: A(7,0)|and B(0,3)

liberstina [14]

Answer:

$\boxed {\boxed {\sf (\frac {7}{2}, \frac{3}{2}) \ or \ (3,5, 1.5) }}$

Step-by-step explanation:

The midpoint is essentially a point with the average of the 2 x-coordinates and the 2 y-coordinates.

The formula is:

$(\frac {x_1+x_2}{2}, \frac{y_1+y_2}{2})$

We are given two points: A (7,0) and B (0, 3). Remember points are written as (x, y).

Therefore,

$x_1= 7 \\y_1=0 \\x_2=0 \\x_2=3$

Substitute the values into the formula.

$(\frac {7+0}{2}, \frac{0+3}{2})$

Solve the numerators first.

$(\frac {7}{2}, \frac{3}{2})$

The midpoint can be left like this because the fractions are reduced, but it can be written as decimals too.

$(3.5, 1.5)$

3 0

3 years ago

2 2/5 in kilometers in 3 3/4 minutes unit rate

Mars2501 [29]

Answer:

Step-by-step explanation:

d = r * t Divide both sides by t

r = d / t

d = distance = 2.25 km

t = time = 3 3/4 minutes = 3.75 minutes

r = 2.25 / 3.75

r = 0.6 km / minute

r = 3/5 km / minute

If the units are different than those given, please state them underneath my answer. I'll get to it as soon as I see your comment.

5 0

3 years ago

Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni

Serjik [45]

Answer:

$x =12\ or\ -8$

Step-by-step explanation:

Given

$(x_1,y_1) = (6,5)$

$(x_2,y_2) = (8,2)$

$(x_3,y_3) = (x,11)$

$Area = 15$

Required

Find x

The area is calculated as thus:

$Area = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$

Substitute values

$15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|$

$15 = \frac{1}{2}|6*(-9) + 8*(6) + x(3)|$

$15 = \frac{1}{2}|-54 + 48 + 3x|$

$15 = \frac{1}{2}|-6 + 3x|$

Multiply through by 2

$2 * 15 = \frac{1}{2}|-6 + 3x| * 2$

$30 = |-6 + 3x|$

Remove absolute sign

$30 = -6 + 3x\ or\ -30 = -6 + 3x$

Add 6 to both sides

$36 = 3x\ or\ -24 = 3x$

Divide by 3

$12 = x\ or\ -8 = x$

$x =12\ or\ -8$

<em>So, the coordinates are (-8, 11) or (12,11)</em>

3 0

2 years ago

In the xy-coordinate plane shown, line L passes through point C and has a slope of -2. A dilation of line {with center A and a s

masya89 [10]

Answer:

C' (-4 , 2)

slope of new line = line "L" = -2

Step-by-step explanation:

C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3

C' (x,y)

x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)

y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)

C' (-4 , 2)

slope of new line = line "L" = -2

8 0

2 years ago