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3 years ago

14

Is three a rational number?

2 answers:

Alexeev081 [22]3 years ago

8 0

Yes because a rational number can be whole numbers, integers, and decimals

Ivanshal [37]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

It is because it can be written in the form of n/1 : 3/1 having the numerator and denominator as integers

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Match the sides based on their relationship to A<br><br> PLEASE ANSWER ASAP

TiliK225 [7]

Answer:

13 hypotenuse

12 adjacent

5 opposite

5 0

3 years ago

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If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.

zmey [24]

Answer:

$a=3$ and $b=5$ .

Step-by-step explanation:

So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

$\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)$

$2(4x+3)=a(x+7)+b(x-3)$

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

$2(4\cdot -7+3)=a(-7+7)+b(-7-3)$

$2(-28+3)=a(0)+b(-10)$

$2(-25)=0-10b$

$-50=-10b$

Divide both sides by -10:

$\frac{-50}{-10}=b$

$5=b$

Now we have:

$2(4x+3)=a(x+7)+b(x-3)$ with $b=5$

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

$2(4\cdot 3+3)=a(3+7)+b(3-3)$

$2(12+3)=a(10)+b(0)$

$2(15)=10a+0$

$30=10a$

Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

4 0

3 years ago

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Which numbers are 3 units from -6 to their correct position on the number line

vfiekz [6]

- 9 and - 3

consider 3 units to the left and right of - 6

- 6 - 3 = - 9 ( 3 units to the left of - 6 )

- 6 + 3 = - 3 ( 3 units to the right of - 6 )

7 0

3 years ago

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Which of the following ratios is equivalent to 24:36?

Ksju [112]

Answer:

D, 20:30

Step-by-step explanation:

At first glance, this does not seem like the correct ratio. But I'll spare you a long intro and get into it:

20:30: Divide both of them by 10

=2:3

2 x 12:3 x 12

24:36

Hope this helps!

4 0

3 years ago

Match the solid figure to the appropriate formula.

AlekseyPX

1. $L \cdot A=\pi r l$ - Cone

2. $V=\frac{4}{3} \pi r^{3}$ - Sphere

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$ - Cylinder

4. $V=\frac{1}{3} B h$ - Pyramid

5. $L . A=p h$ - Prism

Solution:

1. $L \cdot A=\pi r l$

Lateral surface area of cone = $\pi r l$

where r is the radius of the cone and l is the slant height of the cone.

2. $V=\frac{4}{3} \pi r^{3}$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere.

3. $T \cdot A=2 \pi r h+2 \pi r^{2}$

Total surface area of cylinder = $2 \pi r h+2 \pi r^{2}$

where r is the radius of the cylinder and h is the height of the cylinder.

4. $V=\frac{1}{3} B h$

Volume of pyramid = $\frac{1}{3} B h$

where B is the base area of the pyramid and h is the height of the pyramid.

5. $L . A=p h$

Lateral surface area of prism = $p h$

where p is the perimeter of the base and h is the height of the prism.

4 0

3 years ago