Hi there!
Answer:
2x−3y=5
Add 3y to both sides of the equation.
2x=3y+5
Divide each term by 2 and simplify.
Divide each term in 2x=3y+5 by 2
2x2=3y2+52
Reduce the expression by cancelling the common factors.
Cancel the common factor.
2/x2=3y2+52 Divide x by 1
x=3y2+52
Answer:
-2
Step-by-step explanation:
The slope of a line when given two coordinates can be found using the formula
In this case, the first pair of coordinates are and and the second pair of coordinates are and .
Therefore:
= -2
= 7
= 3
= -3
Next, just plug these values into the slope formula from above.
The numerator is 10 (the two negative signs become a positive) and the denominator is -5.
can be simplified by dividing the numerator and denominator by -5 to give or simply -2.
Therefore, the slope of the line is -2.
Answer:
y = 3/4x + 2
Step-by-step explanation:
By looking at the graph, we can easily see that the y-intercept (where the line passes through y) is 2. In the equation y = mx + b. B is the y-intercept. So at the moment, we have, y = mx + 2. Now to find the slope which will take place over "m" all we need is the rise over run. To get this we will look at the points provided, count up the amount to get to the next point above then count to left/right to the point. For this we count up 3 points and 4 points to the right. So we finally get y = 3/4x + 2.
(3/4 = 0.75 if decimal is needed)
Answer:
Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.
Step-by-step explanation:
We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.
Let us find amount of fuel used by autos by dividing the total distance by their mileage.
Let us find the difference of fuel used by both autos.
Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces pounds of carbon.
Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.