Answer:
29568 people cheered for the runners at the start of the race
Step-by-step explanation:
From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.
This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.
First, Convert 1 mile to feet
1 mile = 5280 feet
Hence, the length of the rectangle is 5280 feet and the width is 5 feet.
Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet
5280 feet ÷ 5 feet = 1056
Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.
From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,
∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.
14 × 1056 = 14784 people
This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.
Since the crowd lined up on both sides of the street, then
2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile
2 × 14784 = 29568 people
Hence, 29568 people cheered for the runners at the start of the race.
