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blsea [12.9K]
3 years ago
6

Choose the equation and the inequality needed to answer this question. Trevor tutors French for $15 and hour and scoops ice crea

m for $10 an hour. He is going to work 15 hours this week. At least how many hours does he need to tutor to make more than $180? Let x equal the number of hours he tutors and y be the number of hours he scoops ice cream.
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
6 0

Answer:

One second let me look it up for u :)

Step-by-step explanation:

Gala2k [10]3 years ago
6 0

Answer:

Total number of hours = 15

Let the hours spent tutoring french be x.

Therefore hours spent on scooping ice cream = (15 - x)

Amount:    Tutoring french is $15 an hour, total for x hours = 15x

For scooping ice cream  it is $10 an hour   10*(15 - x) = 150 - 10x  

To make more than $180

15x  + (150 - 10x)  > 180

15x + 150 - 10x > 180

15x - 10x > 180 - 150

5x > 30

x > 30/5

x > 6

trevor needs to tutor 6 hours to make more than 180

Step-by-step explanation:

I hope this helped :)

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Alex

Answer:

The reduced row-echelon form is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The solutions to the system of equations are:

y=-2z-3,\:x=-6z-10

Step-by-step explanation:

To solve this system of linear equations,

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you must:

Step 1: Transform the augmented matrix to the reduced row echelon form.

In an augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

This is the augmented matrix that represents the system.

\left[ \begin{array}{cccc} 1 & -4 & -2 & 2 \\\\ 2 & -11 & -10 & 13 \\\\ -1 & 6 & 6 & -8 \end{array} \right]

It can be transformed by a sequence of elementary row operations to the matrix.

There are three kinds of elementary matrix operations.

  1. Interchange two rows (or columns).
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Using elementary matrix operations, we get that

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Row Operation 4: add -2 times the 2nd row to the 3rd row

Row Operation 5: add 4 times the 2nd row to the 1st row

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

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The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 6 & -10 \\\\ 0 & 1 & 2 & -3 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

x+6z=-10\\y+2z=-3\\0=0

The system has infinitely many solutions.

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Step-by-step explanation:

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