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Alex_Xolod [135]
2 years ago
10

Two teams are selling candy bars to raise money. Team A has $165 saved and they are selling each candy bar for $2. Team B has $7

4 saved and is selling each candy bar for $3. How many candy bars do they both need to sell to have the same amount of money?
Mathematics
1 answer:
devlian [24]2 years ago
6 0

Answer: Each have to sell 91 candy bars to have the same amount of money.

Step-by-step explanation: Suppose x represents the amount of candy bars.

Team A already have $165 and they are selling each candy bar for $2. The mathematical equation that represents the amount of money they have is

A: 165 + 2x

Team B initially has $74 and will sell each candy bar for $3. Then, the mathematical equation representing their amount of money is

B: 74 + 3x

So, to have the same amount of money:

165 + 2x = 74 + 3x

x = 165 - 74

x = 91

<u>Teams A and B will have the same amount of money when each of them </u><u>sell 91 candy bars</u>.

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According to the given confidence interval, we have that:

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<h3>What is the interpretation of a x% confidence interval?</h3>

It means that we are x% confident that the population parameter(mean/proportion/standard deviation) is between a and b.

Additionally, from an interval (a,b), we have that:

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It means that we are 95% sure that the population mean amount of sleep for all students at the high school is between 5.39 and 7.81 hours.

Item b:

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The <em>margin of error</em> is:

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Item c:

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More can be learned about confidence intervals at brainly.com/question/25779324

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