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Alex_Xolod [135]
3 years ago
10

Two teams are selling candy bars to raise money. Team A has $165 saved and they are selling each candy bar for $2. Team B has $7

4 saved and is selling each candy bar for $3. How many candy bars do they both need to sell to have the same amount of money?
Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer: Each have to sell 91 candy bars to have the same amount of money.

Step-by-step explanation: Suppose x represents the amount of candy bars.

Team A already have $165 and they are selling each candy bar for $2. The mathematical equation that represents the amount of money they have is

A: 165 + 2x

Team B initially has $74 and will sell each candy bar for $3. Then, the mathematical equation representing their amount of money is

B: 74 + 3x

So, to have the same amount of money:

165 + 2x = 74 + 3x

x = 165 - 74

x = 91

<u>Teams A and B will have the same amount of money when each of them </u><u>sell 91 candy bars</u>.

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Those little marks on AB and BC denote congruence. That makes the triangle isoceles. That means the base angles are equal. Both 73.

Triangle Sum Theory states all angles of a triangle add to 180.

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Step-by-step explanation:

From the attached diagram, the coordinates are:

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Step-by-step explanation:

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2 years ago
A jar contains 4 white and 4 black marbles. We randomly choose 4 marbles. If 2 of them are white and 2 are black, we stop. If no
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Answer:

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Hope this helps :)

7 0
3 years ago
Read 2 more answers
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