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Anni [7]
2 years ago
7

6a-2(4a-5)=40How do I solve it​

Mathematics
1 answer:
Elza [17]2 years ago
8 0

Answer:

Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.

Step-by-step explanation:

1.) Distribute

6−2(4−5)=40

6−8+10=40

2.) Combine like terms

6a-8a+10=40

-2a+10=40

3.) Subtract 10 from both sides of the equation

-2a+10=40

-2a+10-10=40-10

4.) Simplify

subtract the numbers

-2a+10-10=40-10

-2a=40-10

subtract the numbers

-2a=40-10

-2a=30

-2a=30

5.) Divide both sides of the equation by the same term

-2a=30

\frac{-2a}{-2} =\frac{30}{-2}

6.) Simplify

cancel terms that are in both the numerator or denominator

\frac{-2a}{-2} =\frac{30}{-2}

a=\frac{30}{-2}

Divide the numbers

a=\frac{30}{-2}

a=-15

a=-15

7.) Solution

a=-15

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Find the distance between the two points S (-5,-2) and T (-3,4).
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

S (-5, -2)

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<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-3+5)^2+(4+2)^2}
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  3. Evaluate:                      d = \sqrt{4+36}
  4. Add:                              d = \sqrt{40}
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