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3 years ago

Given AD || GJ. Refer to the figure and provide an appropriate name for BCF and GHF.

Mathematics

2 answers:

SOVA2 [1]3 years ago

8 0

The answer is c I think

Oduvanchick [21]3 years ago

7 0

I think The answer is C

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6) 2 log b + 3 log c

Brilliant_brown [7]

Answer:

5 logbc

Step-by-step explanation:add them up

7 0

3 years ago

Complete the pairs of corresponding parts if ABD congruent to EFC.

Alchen [17]

Remember the notation..

When you have a triangle called ABD, the angles may be called in theses equivalent ways>

angle A is equivalent to ∠ DAB
angle B is equivalent to ∠ ABD
angle D is equivalen to ∠ BDA

Then given that the two triangles are congruent, you can say an

angle B = angle F = ∠ EFC

So the answer is the last option of the list.

5 0

3 years ago

Read 2 more answers

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$