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galina1969 [7]
3 years ago
10

The length of a school bus is 12.6 meters. If 9 school buses park end to end with 2 meters between each one, what's the total le

ngth from the front of the first bus to the end of the last bus?
Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

129.4

Step-by-step explanation:

Calculation for what's the total length from the front of the first bus to the end of the last

First step is to multiply the given number of buses by the length of each one

Hence,

12.6 meters x 9 = 113.4 meters

Second step

Since there are 8 spaces in between we would multiply the 8 spaces by 2 meters

8 x 2 meters = 16

Now let calculate total length from the front of the first bus to the end of the last

16 + 113.4 meters =129.4

Therefore total length from the front of the first bus to the end of the last will be 129.4

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Answer:

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Step-by-step explanation:

A constant is a number that does not have any variables. The additional cost would depend on the number of persons at attendance so the cost would be $10.00p which is not the constant here. Thus, $350.00 is the only constant in this situation.

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3 years ago
Estimate the isoelectric point of a ser–his dipeptide. explain why this value is only an estimate.
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A dipeptide bond connects two amino acids. Ser stands for Serine while His stands for Histidine. Isoelectric point is when all charges of the two amino acids cancel out. This can be estimated by finding the average of the isoelectric points (pI) of the two amino acids.

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Histidine: pI = 7.59

Average pI = (5.68 + 7.59)/2 =<em> 6.635

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3 years ago
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What is the solution to the system of equations? Use any method. {y=−3x+1 {2x+5y=18
Softa [21]

Answer:

So the solution set of the equations are {(-1,4)}

or

the solution is x = -1 and y = 4

Step-by-step explanation:

Equations given to us are

y = -3x + 1                                ..................(i)

2x + 5y = 18                             .................(ii)

To find the value of x and y or the solution set of the system of equations

Now in first equation we see that

y = -3x + 1

Putting this value in equation (ii)

which is

2x + 5y = 18

Putting value of y from (i) in it

2x + 5(-3x + 1) = 18

Opening the bracket and multiplying inside

2x -15x + 5 = 18

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Subtracting 5 from both sides of the equation

-13x + 5 - 5 = 18 -5

-13x = 13

Dividing both sides by -13

\frac{-13x}{-13}=\frac{13}{-13}

Cutting out the same values gives us

x = -1

For value of y

putting value of x in equation (i)

which is

y = -3x + 1

Putting the value

y = -3(-1)+1

y=3+1

y=4

So the solution set of the equations are {(-1,4)}

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the solution is x = -1 and y = 4

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