Answer:
B
Step-by-step explanation:
The zeros ( where the graph crosses the x- axis ) are x = 2 and x = 6
The corresponding factors are (x - 2) and (x - 6) and the equation is the product of the factors, so
y = (x - 2)(x - 6) ← expand using Foil
y = x² - 8x + 12 → B
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
Answer:
y=-3x+1
Step-by-step explanation:
plug in point into x and y, replace -4 as a +b(or any other variable to represent y intercept)
therefore,
7=-3(-2)+b
7=6+b
1=b
y=-3x+1