The object is to get everything except for "h" on one side of the equation.
The equation says that everything on the right side is being multiplied by 1/2.
What do we have to multiply times 1/2 to get 1? The answer is 2.
So multiply both sides by 2 to get rid of the fraction.
2A = (a+b)h
Now we are multiplying h times (a+b) so to get rid of (a+b) we have to divide both sides by that term.
(a+b)/(a+b) is 1
So you are left with: 2A/(a+b) = h
Done!
He should have added 1 to both sides to make the -1 on the right go to 0.
Then it would be 0 + m = -16 + 1 = -15
You can check your work by adding -1 and -15, which does in fact equal -16.
Hope this helped :)
Answer:
The two numbers are <em>32</em> and <em>60</em>.
Step-by-step explanation:
We can create two simultaneous equations to solve this problem using the information given in the question.
Let number 1 = x
Let number 1 = y
x = y - 28 -> ( 1 )
x + y = 92 -> ( 2 )
We can solve simultaneous equations using substitution or elimination. For this question, we will use substitution as it is the easier option.
Substitute ( 1 ) into ( 2 ):
x + y = 92 -> ( 2 )
( y - 28 ) + y = 92
2y - 28 = 92
2y = 120
y = 120 / 2
y = 60 -> ( 3 )
Substitute ( 3 ) into ( 1 ):
x = y - 28 -> ( 1 )
x = ( 60 ) - 28
x = 32
Therefore:
x = 32 , y = 60
True because circles are all the same shape but not all the same size
Hope this helps!
