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fenix001 [56]
2 years ago
10

Which expression is equivalent to startfraction rootindex 4 startroot 6 endroot over rootindex 3 startroot 2 endroot? startfract

ion rootindex 12 startroot 27 endroot over 2 endfraction startfraction rootindex 4 startroot 24 endroot over 2 endfraction startfraction rootindex 12 startroot 55296 endroot over 2 endfraction startfraction rootindex 12 startroot 177147 endroot over 3 endfraction
Mathematics
1 answer:
LuckyWell [14K]2 years ago
4 0

If we write out the expression √4√6/√3√2, then we get the solution to the surd as 2.

<h3>What is a surd?</h3>

A surd is an irrational number which is often shown as a square root. In this case, we have the value; √4√6/√3√2.

This is the same as; 2√6/√6. This now implies that we can cancel out the surd form which is shown as √6 hence the result of the expression is 2.

Learn more about surd:brainly.com/question/24700530

#SPJ4

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PLEASE HELP NOW!!!!!!!!!!!!!!!!!!!
Dahasolnce [82]

Answer:

8 + k² - 6 > 8(k + 2) - 4k when k = 7

Step-by-step explanation:

8 + k² - 6 = 8 + 7² - 6 = 51

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8 + k² - 6 > 8(k + 2) - 4k when k = 7

8 0
3 years ago
Morgan is a real estate agent and most recently made $12,500 on the sale of a home. Her commission she earns in selling homes is
ra1l [238]

Answer:

$104,167 approx.

Step-by-step explanation:

Step one:

Given data

Morgan made $12,500 on the sale of a home.

Her commission she earns in selling homes is 12%

Step two:

let the cost of the home be x

So 12% of x= 12,500

12/100*x= 12,500

0.12*x=12,500

0.12x=12,500

divide both sides by 0.12

x= 12,500/0.12

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x=$104,167

8 0
3 years ago
The sum of three numbers is 11 . The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is
Assoli18 [71]

Answer:

4, 6, 1

Step-by-step explanation:

We can solve this problem using a system of equations:

1) a + b + c = 11

2) 2a + 5b + 6c = 44

3) 4a - b = 10

First, we can substitute the value of b from equation #3 into equation #1:

b = 4a - 10

a + (4a - 10) + c = 11

5a - 10 + c = 11

5a + c = 21

c = 21 - 5a

Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:

2a + 5(4a - 10) + 6(21 - 5a) = 44

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-8a + 76 = 44

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a = 4

b = 4a - 10 = 4(4) - 10 = 6

c = 21 - 5a = 21 - 5(4) = 1

4 0
2 years ago
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