The line segments between (4,-6) and (-6,-16) is 1.
slope = y2 -y1 /x2-x1 = -16+6/-6-4=-10/-10=1
(22 + 15.50 + 2.75) 15
(22 * 15) + (15.50 * 15) + (2.75 * 15)
Given, (9x - 4)(9x + 4) = ax² - b
From algebraic identities:
We know, (a + b)(a - b) = a² - b²
Now, 81x² + 36x - 36x - 16 = ax² - b
81x² - 16 = axis² - b
So ax² = 81x²
a = 81
-b = -16
b = 16
Solution
Therefore, the value of a is 81.
<h2>MyHeritage</h2>
Answer:
is this your only question?
Answer:
The correct option is;
DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)
Step-by-step explanation:
Given that we have;
1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC
2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC
3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC
Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;
AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))
∴ (sin(m∠ADE)) = (sin(m∠ABC))
m∠ADE) = m∠ABC).
