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larisa86 [58]
3 years ago
15

Algebra 1 Assignment! Help needed as soon as possible! thanks so much to whoever helps! have a nice day

Mathematics
1 answer:
mezya [45]3 years ago
8 0

Answer:

Step-by-step explanation:

go-kart = Gk

Head sock = Hs   (what?  a sock in the head?  :/ what ?? )

Laser tag = Lt

Eq 1 ) Gk + Hs + Lt = 33

Eq 2) 2Gk + Hs + 0Lt = 48

Eq 3) 2Gk + Hs + 2Lt =64

This is a system of equations  w/ 3 unknowns and 3 equations so we can solve this. :)

subtract Eq 2 from Eq 3

  2Gk +Hs +2Lt =64

-(2Gk +Hs +0Lt =48)

0Gk + 0 Hs +2Lt = 16

Lt =8    

so one Laser tag game is 8 dollars.. good... now use  8 in Eq. 1 and 3 for Lt price

Eq 1a) Gk + Hs +8 =33    simplify

Eq 1b) Gk + Hs = 25

Eq 3a) 2Gk +Hs +2(8) = 64  simplify

Eq3b) 2Gk + Hs =48

subtract Eq 1b from Eq 3b

2Gk + Hs =48

-(Gk + Hs =25)

Gk = 23

so one Gk ride costs 23 dollars and plug this into Eq 1

23 + Hs + 8 = 33

Hs = 2

Question 1  )  Gk = 23  Hs = 2 Lt = 8

solve new systems, same as above but  with the new prices

Eq 1r ) Gk + Hs + Lt = 18

Eq 2r) 2Gk + Hs + 0Lt = 29

Eq 3r) 2Gk + Hs + 2Lt =35

subtracting 2r from 3r we get 2Lt = 6   then Lt =3  for the new price

plug that into 1r and 3r

Eq 1br) Gk + Hs = 15

Eq 3br) 2Gk +Hs = 29

subtract 1br from 3br

 Gk = 14

plug this into 1r

Hs =1

Question 2 ) Gk=14 Hs =1 Lt=3

Question 3)  wants 2 Hs and 2 Lt

w/o coupon the activities cost 2 ( 2+8)  = 20 dollars

but there is no coupon for 2 of each game

so  no, don't buy a coupon.. just play at full price

Hustler side note.. buy two of the 18 coupons and sell the 2 Gk rides to your   teacher for 15 dollars each, still a good deal to guarantee a good grade on your Home Work ..  (30 total)...... and get your games for just 6 dollars... excellent deal for you   :)

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z, equals, start fraction, start text, d, a, t, a, space, p, o, i, n, t, end text, minus, start text, m, e, a, n, end text, divided by, start text, s, t, a, n, d, a, r, d, space, d, e, v, i, a, t, i, o, n, end text, end fraction

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The grades on a history midterm at Almond have a mean of \mu = 85μ=85mu, equals, 85 and a standard deviation of \sigma = 2σ=2sigma, equals, 2.

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z

z

z

​  

 

=  

standard deviation

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=  

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=  

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1

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The grades on a geometry midterm at Almond have a mean of \mu = 82μ=82mu, equals, 82 and a standard deviation of \sigma = 4σ=4sigma, equals, 4.

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=  

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=  

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