For the function g(x)=\x-51 +4, g(-6) =

Mathematics

1 answer:

natulia [17]3 years ago

8 0

Answer:g(-6)= -53

*All you have to do is plug -6 for x so its going to look something like...

g(-6)= -6-51+4

g(-6)= -57+4

g(-6)= -53

You might be interested in

What is 7/4 times 7/3

yaroslaw [1]

49/12

Just mulitply the top and the bottom across.

7*7/4*3

49/12

7 0

3 years ago

Eloise made a list of some multiples of 8/5 write 5 fractions that can be in Eloise list

alexgriva [62]

This question is asking for a list of fractions, that when you pull out common factors, they will all simplify back to the 8/5 fraction.

So if 2 is the common factor, you multiply the numerator and denominator by 2.

2: (8*2)/(5*2)= 16/10

3: (8*3)/5*3)= 24/15

4: (8*4)/(5*4)= 32/20

5: (8*5)/(5*5)= 40/25

10: (8*10)/5*10)= 80/50

Eloise's Potential List:
16/10, 24/15, 32/20, 40/25, 80/50

If you simplify any of these fractions above, you will get 8/5 again.

To work backwards:
80/50: 10 goes into 80, 10 goes into 50= 8/5

16/10: 2 goes into 16, 2 goes into 10= 8/5

Hope this helps! :)

4 0

3 years ago

Y=x^2-25 is it linear?

Svetllana [295]

Answer:

yes it is i think

7 0

3 years ago

Read 2 more answers

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$