The given function is,
The graph can be drawn as,
The period will be distance between two consequetive maximas,
Thus, period is correct.
The amplitude can be determined as,
Thus, amplitue is incorrect.
The range is,
Thus, the range is correct.
The midline is,
Thus, the midline is correct.
Thus, option (b) is the solution.
The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
This only happens when the ordinary ratio is greater than one, the terms of the sequence will get bigger and bigger, and if you add larger numbers you won't get a definitive answer.
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