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Debora [2.8K]
2 years ago
5

Suppose you put two white socks and one brown sock in a bag and you

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
5 0

Answer:

That you will most likely always get white.

Step-by-step explanation:

Since they got it 13 times.

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3m+n=10<br>5m-2n=2<br>what is the answer for this one ​
svlad2 [7]

Answer:

m = 2

n = 4

Step-by-step explanation:

Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:

3m + n = 10

multiply both sides by 2

6m + 2n = 20

now, in both of your equations you have 2n so you can add the two equations:

6m + 2n = 20

+ 5m - 2n = 2

11m = 22

divide both sides by 11

m = 2.

Now, plug this value into the original equation, 3m + n = 10:

3 * 2 + n = 10

6 + n = 10

subtract 6 from both sides

n = 4

6 0
2 years ago
Approximate the square root of 12 to the nearest integer helppppppp!!!!!!!!
oee [108]

Answer:

3

Step-by-step explanation:

Well the square root of 12 is 3.464 and 12 squared is 144, and an intiger is a whole number no decimal or fraction. So round 3.464 to the nearest whole is 3. Hope this helps(:

3 0
3 years ago
Help pleaseeee can anyone explain and write the answer please
Natali [406]

Answer:

you type in the answer if you know it

Step-by-step explanation:

3 0
2 years ago
Find the area of this figure (sides meet at right angles)
Marrrta [24]

Answer:

60 cm²

Step-by-step explanation:

Just divide the figure in parts and then find their areas separately. At last, find the area of the whole figure by adding the areas of the parts

6 0
2 years ago
"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim
iren [92.7K]

Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that  since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

5 0
3 years ago
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