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2 years ago

NEED MAJOR HELP WITH HW! ps: will make brainliest!

Mathematics

1 answer:

Solnce55 [7]2 years ago

7 0

1.2/5
2.1/30
3.4/5 of 45 minutes is 36 minutes
4.7/10
5.3/14
6.12/30
7.1/2
8.5/16
9.3/12
3.3/20

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Jessica purchased a 600-minute pre-paid phone card and called her sister at college. After talking to her sister "t" minutes, sh

Vesna [10]

Answer:

1) 600-t

2) 600-t=65

=>t=535

6 0

2 years ago

The difference of a number and 6 is the same as 5 times the sum of the number and 2. What is the number?

S_A_V [24]

Step-by-step explanation:

Lets consider the unknown number as x

according to the question,

6-x= 5(x+2)

6-x= 5x+10

-x-5x=10-6

-6x=4

x=4/-6= 2/-3

x= -2/3

<em>hope this helps </em>

<em>please mark me as brainliest.</em>

6 0

2 years ago

The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr

IgorC [24]

<h2><u>Answer with explanation</u>:</h2>

Let $\mu$ be the population mean.

As per given , we have

$H_0:\mu \leq4\\\\ H_a: \mu >4$

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given $\sigma=1$ , so we perform one-tailed z-test.

Test statistic : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where $\mu$ = Population mean

$\sigma$ = Population standard deviation

n= sample size

$\overline{x}$ = Sample mean

For n= 18 , $\overline{x}=4.50$ , $\sigma=1$ , $\mu =4$ , we have

$z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12$

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

3 0

3 years ago

−11.9/−1<br> picture bellow is more clear

scZoUnD [109]

Answer:

11.9

Step-by-step explanation:

-11.9/-1

so the both cancel out each other

so it will just be 11.9 ,since it is -1

7 0

2 years ago

Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places

Sergeeva-Olga [200]

Solution: Telemarketing. the probability that a call will reach a live person is 0.2. the calls are independent. (a) a telemarketer places 5 calls. what is the probability that none of them reaches a live person.

Answer: The given random experiment can be considered as binomial experiment with probability of success = 0.2 and number of trials = 5

Therefore, we have:

$n=5,p=0.2,q=(1-p)=1-0.2=0.8$

Let x be the number calls that reach to live person.

We have to find $P(x=0)$

Using the binomial probability distribution, we have:

$P(x=0)=\binom{5}{0}0.2^{0} (1-0.2)^{5-0}$

$=1 \times 1 \times 0.8^{5}$

$=0.3277$

Therefore, the probability that none of them reaches a live person is 0.3277

6 0

3 years ago