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Cloud [144]
3 years ago
7

Scott trained for the marathon.

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

a)

<u>Day 1</u>

  • 70 min for 10 km
  • Rate = 70/10 = 7 min/km

<u>Day 10</u>

  • 2h40 min for 20 km
  • 2*60+40 = 160 min for 20 km
  • Rate = 160/20 = 8 min/km

<u>Day 20</u>

  • 4 h 15 min for 30 km
  • 4*60 + 15 = 255 min for 30 km
  • Rate = 255/30 = 8.5 min / km

b)

<u>From the rate change we see:</u>

  • 1 min increase when the distance increases from 10 km to 20 km
  • 0.5 min increase when distance increases from 20 km to 30 km

So we see 1 min increase per twice the distance increase

  • With the same rate increase we can expect 1 min increase from 20 km to 40 km, which gives us the rate of 9 min/km
  • With same logic we get 9.055 km/min rate for 44 km distance

<u>Total time it takes:</u>

  • 9.055*44 = 398.42 min = 398.42*1/60 min = 6 h and 38.42 min
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From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?
Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

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E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

4 0
3 years ago
Nina can stitch 3 of a dress in 4 hours. If drepresents the number of dresses and h represents the number of hours, which equati
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Answer:

C. d= 1/6h

Step-by-step explanation:

2/3 dress in 4 hours

We need to find out how much of a dress can be finished per hour.

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Answer:

I am 90% sure that the answer is M'N'O' is 90*

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A line segment MN is shown as M = -1,1 and N= -5,4 this makes a diagonal line across the grid. Another line segment NO is shown with O as ordered pair negative 1, 4. Angle MNO is rotated 90 degrees counterclockwise about the origin to form angle M′N′O′. this is where the angles meet, Rotating the shape (or the angles) does not change the degree of the angle of the shape. I am 99% sure that an 90* angle would be formed. but im just in middle school so what do i know?

6 0
3 years ago
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