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3 years ago

Scott trained for the marathon.

Mathematics

1 answer:

slamgirl [31]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

Day 1

70 min for 10 km
Rate = 70/10 = 7 min/km

Day 10

2h40 min for 20 km
2*60+40 = 160 min for 20 km
Rate = 160/20 = 8 min/km

Day 20

4 h 15 min for 30 km
4*60 + 15 = 255 min for 30 km
Rate = 255/30 = 8.5 min / km

From the rate change we see:

1 min increase when the distance increases from 10 km to 20 km
0.5 min increase when distance increases from 20 km to 30 km

So we see 1 min increase per twice the distance increase

With the same rate increase we can expect 1 min increase from 20 km to 40 km, which gives us the rate of 9 min/km
With same logic we get 9.055 km/min rate for 44 km distance

Total time it takes:

9.055*44 = 398.42 min = 398.42*1/60 min = 6 h and 38.42 min

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vaieri [72.5K]

Answer:

The length of the rectangle is 30 feet.

Step-by-step explanation:

Because the equation for area is length times width, you would have to set the two equations to seventy and multiply them.

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Then, you would have to subtract ten from both sides, cancelling it from the left side.

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3 years ago

Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

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Answer with explanation:

The given expression is:

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Option C

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2 years ago

Marty paid $121 for shoes and clothes. He paid $45 more for clothes than he did for shoes. How much did Marty pay for the shoes?

yarga [219]

121 - 90 = 31 for the shoes.

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3 years ago

Please help me figure out the right answer and if you don’t know please don’t answer the question

Degger [83]

Answer:

Figure A and C

Step-by-step explanation:

3 0

2 years ago

Please help! Help me with the steps as well not just answers:/

serious [3.7K]

For question 1 you need to find the sqared values of the hypotenuse, which has a length of 15, and leg b, which has a length of 12. This gives you a hypotenuse of 225 and a leg which is 144. Subtract your given leg squared from your hypotenuse squared (aka 225-144). This leaves you with 81. Now find the square root of this, which is 9.

For question 2 you need to find the squared value of legs a and b. Leg a has an initial length of 6, which squared is 36. The same applies for leg b. Now add 36 to 36 to get 72. All you have to do is find the square root of that to have your answer. Since 72 isn't a perfect square, just simplify the root to 3 root 8, aka
$3 \sqrt{8}$
For question 3, repeat the process used in question 1. The square of a square root is the original number (ex: the sqare root of 3 squared is 3). Subtract 7 from 19 to get 12. 12 isn't a perfect square, so simplify the root. You should end up with 2 root 3, aka
$2 \sqrt{3}$

For question 4 you must find the sqared value of a, b, and c. The sum of the sqared values of a and b is equal to the squared value of c. If c is 10 and a and b are both x, then the formula is
${x}^{2} + {x}^{2} = 100$
or
$2 {x}^{2} = 100$
Next, simplify this by first dividing by 2 on each side. You are then left with x squared equals 50. Simplify the root to 5 root 2, aka
$5 \sqrt{2}$

For question 5 you need to find the squared value of 47 and 25. This leaves you a hypotenuse of 2209 and a width of 625. Subtract 625 from 2209. This leaves you with 1584. Find the sqare root of this to find your length. Since it isn't a perfect square, simplify the root to get 12 root 11, aka
$12 \sqrt{11}$

I hope this helps clear things up for you!

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3 years ago