Answer:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
(1) 4mn × 6mp × 3mnp
= 4 × 6 × 3 ( mn × mp × mnp)
= 72 × (m³n²p²)
72m³n²p²
sorry, I'm busy, won't be able to complete it
10 more times
On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10
Let the amount invested at 4% be = x
Let the amount invested at 3% be = y
Given is:
or
.... (1)
As, total income for the two investments is $194, so equation is:
....(2)
Putting value of x from (1) in (2)




And x=5200-y

Hence, money invested at 4% is $3800 and money invested at 3% is $1400
The perimeter of a rectangle is 2L + 2W, where L and W are the length and width, respectively. The dimensions of the garden are given, 6 x 12 ft.
The amount of fencing needed is 2(6) + 2(12) = 12 + 24 = 36 ft of fencing