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3 years ago

Write the equation of a vertical line that passes through 2, 7

Mathematics

1 answer:

Novay_Z [31]3 years ago

6 0

A vertical line is up and down so it will have the x coordinate

x=2

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Write an equivalent fraction 11/50 33/

olga2289 [7]

An equivalent fraction for 11/50=33/150

4 0

3 years ago

Read 2 more answers

How can i find the midpoint of a line segment ?

eimsori [14]

Answer:

add both x coordinates and divide them by 2.

add both y coordinates and divide them by 2.

Now final product should be (x,y)

Step-by-step explanation:

Example.

let's take 2 points:

(2,5) and (7, 9)

let's add both x coordinates.

2+7 = 9

now add both y coordinates.

5+9 = 14

Now divide both by 2.

Final answer should be (4.5, 7) = this is your midpoint

8 0

3 years ago

Convert 7,850 mm into m.<br> m

meriva

Answer:

Going millimeters to meters, the answer is 7.85

Step-by-step explanation:

You divide the millimeters by 1000 to get the meters.

6 0

3 years ago

Read 2 more answers

Help plz! Evaluate the following definite integral:<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_%7B-a%7D%20%7B%28a%5E%7

s344n2d4d5 [400]

Just use the power rule:

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=a^2t-\dfrac13t^3\bigg|_{t=-a}^{t=a}$

We also could have use the fact that the integrand is even to write

$\displaystyle\int_{t=-a}^{t=a}(a^2-t^2)\,\mathrm dt=2\int_{t=0}^{t=a}(a^2-t^2)\,\mathrm dt=2\left(a^2t-\dfrac13t^3\bigg|_{t=0}^{t=a}\right)$

I'll continue with this expression since it's easier to evaluate (if only a little):

$2a^3-\dfrac23a^3=\dfrac43a^3$

7 0

3 years ago

Quadrilateral KLMN has vertices of K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4) Find the length of MN

Olenka [21]

Answer:

The length of MN is $\sqrt{5}$ units.

Step-by-step explanation:

The given Quadrilateral KLMN has vertices at K(-4,-1), L(-1,-1) M(-2,-5) and N(-4,-4).

We use the distance formula to find the length of MN.

$|MN|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We plug in the values to get

$|MN|=\sqrt{(-4--2)^2+(-4--5)^2}$

$|MN|=\sqrt{(-2)^2+(1)^2}$

$|MN|=\sqrt{4+1}$

$|MN|=\sqrt{5}$

The length of MN is $\sqrt{5}$ units.

3 0

4 years ago