Answer:
Step-by-step explanation:
We know the perimeter of a triangle is the sum of all the sides( two legs and one hypotenuse).
By pythagoras we know that

and the perimeter is
.
Since P=24 and a=6 we have these equations:

From the last equation we have
. Replace h in the first equation we get that


and h=18-8=10
Answer:
16 36 169 100
Step-by-step explanation:
If 42 is the area and the formula is bh1/2 then 42 times 2 = 6x to sold x we do 84 divided by 6 and x= 14 the height of the triangle.is 14
Hmm, the 2nd derivitve is good for finding concavity
let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient
so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x
so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points
f'(-1)>0
f'(1.5)<0
f'(3)>0
so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)
we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense
local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))