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bekas [8.4K]
3 years ago
9

Solve for x, 6x =48 please asap​

Mathematics
2 answers:
valkas [14]3 years ago
7 0

Answer:

8

Step-by-step explanation:

48/6=8

tigry1 [53]3 years ago
4 0

Answer:

8

Step-by-step explanation:

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Im Timed Help Pls I need help with math problem
Nady [450]

Answer:

35.36 i think

Step-by-step explanation:

40%x68=27.2

20%x27.2=5.44

27.2+5.44=32.64

68-32.64=35.36

$35.36

7 0
3 years ago
Which ordered pair is a solution of the equation y equals x minus 3
Rom4ik [11]
Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps 
6 0
3 years ago
0.48 divided by 0.06 with shown work please help!
Valentin [98]

Answer: 8

Step-by-step explanation:

2 To convert to a percent, multiply the decimal by 100.

8\times 100=800

8×100=800

800

800%

6 0
3 years ago
A linear model is given for the data in the table: y=1.25x+2.
Fed [463]

Answer:

Option A

Step-by-step explanation:

Given that A linear model is given for the data in the table: y=1.25x+2.

Let us write observed values for each x and also the predicted values as per equation.

x            2     3        4      8    10      16    20    24    Total

y((O)      3      4        7     12   16      22   28    30

y(P)     4.5   5.75      7     12   14.5   22   27    32

DEv    1.5    1.75      0       0     1.5     0      1       2     7 75

where y(0) represents observed y or y in the table given

y(P) gives values of y predicted as per the equation 1.25x+2

Dev represents the absolute difference

Hence answer is option

A.7.75

8 0
3 years ago
A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the
Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision    Variable        Constraint              Constraint

A                     65                          65                         100

B                     80                          80                         80

C                     90                         90                          90

                      14100                    300                        300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

                             A              B                  C                Unit price

Need of X          2                 1                   1                     $20

Need of Y           2                3                  2                    $30

Need of Z           2                2                  3                    $25

Price of  

manufac -      $200          $240            $220      

turing

Now,  for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.  

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160  

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit  --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

{(100 - A) + (80 - B) +(90 - C) } + \$40

This should be subtracted from profit.

So, we have to maximize the profit  

Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

2A + B +C \le 300 due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

A \le 100

B \le 80

C \le 90

 

and A, B, C \ge 0 because they are positive quantities

The objective is:

\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}

A, B, C \to Decision Varaibles;

Constraint are:

A \le 100 \\ \\  B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0

6 0
3 years ago
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