Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer: 0.7
Locate the tenths place which is just to the right of the decimal point. We see a 6 in this spot. Just to the right of this 6 is the value 8. Since 8 is larger than 5, we bump the 6 up to 7 and erase everything else to the right. You can think of it like this
0.687 ---> 0.6 which bumps up to 0.7
This is like saying 687 is closer to 700 than it is to 600
Buying books, your dorm and maybe a ride to get to school
I think the newsstand has 87 papers in the beginning of the day
10 oranges = $1
5 oranges = $?
To get from 10 to 5 you divide by 2 so that’s what you do with the $1 so it would be $0.50
